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3x^2+13x+14=2x^2
We move all terms to the left:
3x^2+13x+14-(2x^2)=0
determiningTheFunctionDomain 3x^2-2x^2+13x+14=0
We add all the numbers together, and all the variables
x^2+13x+14=0
a = 1; b = 13; c = +14;
Δ = b2-4ac
Δ = 132-4·1·14
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{113}}{2*1}=\frac{-13-\sqrt{113}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{113}}{2*1}=\frac{-13+\sqrt{113}}{2} $
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